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Answer.swift
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Answer.swift
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// Try POH
// author: Leonardone @ NEETSDKASU
// =============================================================
func ti(s :String) -> Int { if let v : Int = Int(s) { return v } else { return 0 } }
func gs() -> String { if let s : String = readLine() { return s } else { return "" } }
func gi() -> Int { return ti(gs()) }
func gss() -> [String] { return gs().characters.split{ $0 == " " }.map{ String($0) } }
func gis() -> [Int] { return gss().map(ti) } // [Type] は Array<Type> の糖衣構文的な？
func ngt<T>(n :Int, f :() -> T) -> [T] { var a : [T] = [T](); for _ in 1...n { a.append(f()) }; return a }
func ngs(n :Int) -> [String] { return ngt(n, f: gs) }
func ngi(n :Int) -> [Int] { return ngt(n, f: gi) }
func ngss(n :Int) -> [[String]] { return ngt(n, f: gss) }
func ngis(n :Int) -> [[Int]] { return ngt(n, f: gis) }
func Bv2(a :[Int]) -> (Int, Int, [Int]) { return (a[0], a[1], [Int](a[2..<a.count])) }
func Bv3(a :[Int]) -> (Int, Int, Int, [Int]) { return (a[0], a[1], a[2], [Int](a[3..<a.count])) }
func Bv4(a :[Int]) -> (Int, Int, Int, Int, [Int]) { return (a[0], a[1], a[2], a[3], [Int](a[4..<a.count])) }
func Bv5(a :[Int]) -> (Int, Int, Int, Int, Int, [Int]) { return (a[0], a[1], a[2], a[3], a[4], [Int](a[5..<a.count])) }
// =============================================================
func solve() {
let s = gs().characters
var c = 0
for i in s.startIndex ..< s.endIndex {
let sb = String(s[i ..< s.endIndex].prefix(3))
if sb == "cat" {
c += 1
}
}
print(c)
}
solve()