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daynightratio.h: Improve codestyle, minor optimisations (#8453)
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paramat committed Apr 7, 2019
1 parent a222ff4 commit 0cc85a7
Showing 1 changed file with 34 additions and 30 deletions.
64 changes: 34 additions & 30 deletions src/daynightratio.h
Expand Up @@ -22,47 +22,51 @@ with this program; if not, write to the Free Software Foundation, Inc.,
inline u32 time_to_daynight_ratio(float time_of_day, bool smooth)
{
float t = time_of_day;
if(t < 0)
t += ((int)(-t)/24000)*24000;
if(t >= 24000)
t -= ((int)(t)/24000)*24000;
if(t > 12000)
t = 24000 - t;
float values[][2] = {
{4250+125, 150},
{4500+125, 150},
{4750+125, 250},
{5000+125, 350},
{5250+125, 500},
{5500+125, 675},
{5750+125, 875},
{6000+125, 1000},
{6250+125, 1000},
if (t < 0.0f)
t += ((int)(-t) / 24000) * 24000.0f;
if (t >= 24000.0f)
t -= ((int)(t) / 24000) * 24000.0f;
if (t > 12000.0f)
t = 24000.0f - t;

const float values[9][2] = {
{4250.0f + 125.0f, 150.0f},
{4500.0f + 125.0f, 150.0f},
{4750.0f + 125.0f, 250.0f},
{5000.0f + 125.0f, 350.0f},
{5250.0f + 125.0f, 500.0f},
{5500.0f + 125.0f, 675.0f},
{5750.0f + 125.0f, 875.0f},
{6000.0f + 125.0f, 1000.0f},
{6250.0f + 125.0f, 1000.0f},
};
if(!smooth){

if (!smooth) {
float lastt = values[0][0];
for(u32 i=1; i<sizeof(values)/sizeof(*values); i++){
for (u32 i = 1; i < 9; i++) {
float t0 = values[i][0];
float switch_t = (t0 + lastt) / 2;
float switch_t = (t0 + lastt) / 2.0f;
lastt = t0;
if(switch_t <= t)
if (switch_t <= t)
continue;

return values[i][1];
}
return 1000;
}

if (t <= 4625) // 4500 + 125
if (t <= 4625.0f) // 4500 + 125
return values[0][1];
else if (t >= 6125) // 6000 + 125
else if (t >= 6125.0f) // 6000 + 125
return 1000;
for (u32 i=0; i < sizeof(values) / sizeof(*values); i++) {
if (values[i][0] <= t)
continue;

float td0 = values[i][0] - values[i-1][0];
float f = (t - values[i-1][0]) / td0;
return f * values[i][1] + (1.0 - f) * values[i-1][1];
}
return 1000;
for (u32 i = 0; i < 9; i++) {
if (values[i][0] <= t)
continue;

float td0 = values[i][0] - values[i - 1][0];
float f = (t - values[i - 1][0]) / td0;
return f * values[i][1] + (1.0f - f) * values[i - 1][1];
}
return 1000;
}

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